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16t^2-191t-30=0
a = 16; b = -191; c = -30;
Δ = b2-4ac
Δ = -1912-4·16·(-30)
Δ = 38401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-191)-\sqrt{38401}}{2*16}=\frac{191-\sqrt{38401}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-191)+\sqrt{38401}}{2*16}=\frac{191+\sqrt{38401}}{32} $
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